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Parse arguments: no args & Vector object args work, tuples and bare numerics still do not

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John McCardle 2024-03-30 22:51:55 -04:00
parent 1c12e8719c
commit 8871f6be6e
1 changed files with 9 additions and 3 deletions
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12
src/PyVector.cpp
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@ -55,16 +55,22 @@ int PyVector::init(PyVectorObject* self, PyObject* args, PyObject* kwds)
{ {
using namespace mcrfpydef; using namespace mcrfpydef;
static const char* keywords[] = { "x", "y", nullptr }; static const char* keywords[] = { "x", "y", nullptr };
PyObject* leader; PyObject* leader = NULL;
double x=0, y=0; double x=0, y=0;
if (!PyArg_ParseTupleAndKeywords, args, kwds, "|Of", leader, &y) if (!PyArg_ParseTupleAndKeywords(args, kwds, "|Of", const_cast<char**>(keywords), &leader, &y))
{ {
//PyErr_SetString(PyExc_TypeError, "mcrfpy.Vector requires a 2-tuple or two numeric values"); //PyErr_SetString(PyExc_TypeError, "mcrfpy.Vector requires a 2-tuple or two numeric values");
self->data = sf::Vector2f();
return 0;
}
else if (leader == NULL || leader == Py_None)
{
self->data = sf::Vector2f();
return 0; return 0;
} }
// if the "r" arg is already a vector, yoink that color value // if the "r" arg is already a vector, yoink that color value
if (PyObject_IsInstance(leader, (PyObject*)&PyVectorType)) else if (PyObject_IsInstance(leader, (PyObject*)&PyVectorType))
{ {
self->data = ((PyVectorObject*)leader)->data; self->data = ((PyVectorObject*)leader)->data;
return 0; return 0;